To open a cd in a specified file

[timmera]

I want to burn a number of different XML-files on a cd. When someone opens the cd, there is one specific file that has to be shown at first. Anybody knows how to do that?

[Chris]

Whats the file name?

...and yes it can be done.

[timmera]

Whats the file name?

...and yes it can be done.

The name of the file is index.html

[timmera]

Whats the file name?

...and yes it can be done.

Hello Chris, see my answer, can you pse help me further?

[cozofdeath]

Since autorun only run applications and an html file is considered a document your going to have to do something different. One option would be to add a batch file where your autorun file is. To do that open notepad and type this in it "@start index.html" without the quotes and save it with a .bat extension instead of a .txt and make the Save as type: to be all files. Then in your autorun file add the line "open=name of your .bat file" without the quotes.

The second option would be to download a program like WinOpen and put it where your autorun file is then adding this line to your autorun file "open=winopen \index.html" without quotes.

[timmera]

Thanks, I'll try it as specified. I will inform you about the results.

[timmera]

Since autorun only run applications and an html file is considered a document your going to have to do something different. One option would be to add a batch file where your autorun file is. To do that open notepad and type this in it "@start index.html" without the quotes and save it with a .bat extension instead of a .txt and make the Save as type: to be all files. Then in your autorun file add the line "open=name of your .bat file" without the quotes.

The second option would be to download a program like WinOpen and put it where your autorun file is then adding this line to your autorun file "open=winopen \index.html" without quotes.

I used the 2nd option, it worked fine. Thanks for the advice.