Guest Lived Backwards Posted January 31, 2004 Report Share Posted January 31, 2004 I recieved this little maths trick and it worked for me......Key into the calculator the first 3 digits of your phone number (not area code). >Multiply by 80. >Add 1. >Multiply by 250. >Add last 4 digits of your phone number. >Add last 4 digits of your phone number again. >Subtract 250. >Lastly, divide by 2. Is this your phone number??? how about you??? Quote Link to comment Share on other sites More sharing options...
Tony Posted January 31, 2004 Report Share Posted January 31, 2004 yep it worked for me :o Tony Quote Link to comment Share on other sites More sharing options...
Sir Radfordin Posted January 31, 2004 Report Share Posted January 31, 2004 Worked here Quote Link to comment Share on other sites More sharing options...
doug Posted January 31, 2004 Report Share Posted January 31, 2004 Let x be the first 3 digits, i.e. 10000 times smaller than the actual numerical value.Let y be the last 4 digits, then the algorithm becomes{250[80x+1]+2y-250}/2if you multiply out the 250[80x+1] it becomes 20000x + 250see what's happening?Then the 250's cancel outthen divide by 2 and you havex0000 plus ySimple really but a good party trick Quote Link to comment Share on other sites More sharing options...
monkey Posted January 31, 2004 Report Share Posted January 31, 2004 :D i like that Quote Link to comment Share on other sites More sharing options...
moon Posted January 31, 2004 Report Share Posted January 31, 2004 I've got five phone numbers and it worked on all of them. Quote Link to comment Share on other sites More sharing options...
moon Posted January 31, 2004 Report Share Posted January 31, 2004 :D Quote Link to comment Share on other sites More sharing options...
trackrat Posted January 31, 2004 Report Share Posted January 31, 2004 Worked all right :rolleyes: Quote Link to comment Share on other sites More sharing options...
Guest Lived Backwards Posted January 31, 2004 Report Share Posted January 31, 2004 Let x be the first 3 digits, i.e. 10000 times smaller than the actual numerical value.Let y be the last 4 digits, then the algorithm becomes{250[80x+1]+2y-250}/2if you multiply out the 250[80x+1] it becomes 20000x + 250see what's happening?Then the 250's cancel outthen divide by 2 and you havex0000 plus ySimple really but a good party tricki think i should have paid more attention in school to our maths lessons as i got lost after the third line!!!!! Quote Link to comment Share on other sites More sharing options...
Hurdy Posted January 31, 2004 Report Share Posted January 31, 2004 No :( I feel left outMy telephone number only has 6 digits Quote Link to comment Share on other sites More sharing options...
Guest Drovers Dog Posted February 1, 2004 Report Share Posted February 1, 2004 Let x be the first 3 digits, i.e. 10000 times smaller than the actual numerical value.Let y be the last 4 digits, then the algorithm becomes{250[80x+1]+2y-250}/2if you multiply out the 250[80x+1] it becomes 20000x + 250see what's happening?Then the 250's cancel outthen divide by 2 and you havex0000 plus ySimple really but a good party trick:P God, just when my Alegbra Teacher was gone forevermore!!! There you are!!! :innocent: :D Quote Link to comment Share on other sites More sharing options...
Guest Drovers Dog Posted February 1, 2004 Report Share Posted February 1, 2004 No :( I feel left outMy telephone number only has 6 digits:P use the first two!! :innocent: :D Quote Link to comment Share on other sites More sharing options...
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